Since April 2008, 810 persons infected with Salmonella Saintpaul with the same g
ID: 308885 • Letter: S
Question
Since April 2008, 810 persons infected with Salmonella Saintpaul with the same genetic fingerprint have been identified in 36 states and the District of Columbia. These were identified because clinical laboratories in all states send strains from ill persons to their state public health laboratory for characterization.
The number of ill persons identified in each state is as follows: Arkansas (10 persons), Arizona (39), California (10), Colorado (8), Connecticut (4), Florida (1), Georgia (18), Idaho (3), Illinois (78), Indiana (11), Kansas (14), Kentucky (1), Maine (1), Maryland (25), Massachusetts (18), Michigan (4), Minnesota (2), Missouri (12), New Hampshire (3), Nevada (4), New Jersey (4), New Mexico (85), New York (25), North Carolina (5), Ohio (6), Oklahoma (19), Oregon (7), Pennsylvania (6), Rhode Island (3), Tennessee (6), Texas (342), Utah (2), Virginia (22), Vermont (1), Washington (4), Wisconsin (6), and the District of Columbia (1).
What percent of the cases are from the state with the most cases?
Explanation / Answer
The most number of cases that are 342 is in Texas.
(Total number of cases in texas/Total Cases)*100
Therefore, the required percentage is (342/810)*100=42.22%
Answer=42.22%