A frieght train left astation at 12 noon, going north at a rate of 50 miles perh

Question

A frieght train left astation at 12 noon, going north at a rate of 50 miles perhour. At 1 PM a passenger train left the same station, goingsouth at a rate of 60 miles per hour. At what times were thetrains 380 miles apart?
a. 3:00 PM b.4:00 PM c.4:30 PM d.5:00 PM e.5:30 PM A frieght train left astation at 12 noon, going north at a rate of 50 miles perhour. At 1 PM a passenger train left the same station, goingsouth at a rate of 60 miles per hour. At what times were thetrains 380 miles apart?
a. 3:00 PM b.4:00 PM c.4:30 PM d.5:00 PM e.5:30 PM e.5:30 PM

Explanation / Answer

Lets make a chart... NAME                                     RATE                              TIME                                        DISTANCE TRAIN1                                 50m/h                                 t+1*                                          50(t+1) TRAIN2                                   60m/h                                t                                             60t (this is t+1 because train 1 left at 12p.m. and train 2 leftat 1p.m., so you need to add that extra hour inbetween) Lets solve for t first... 50(t+1)+60t=380 add the two distances and set them equal to380miles 50t+50+60t=380 simplify and solve 110t+50=380 110t=330 t=3 or 3 hours So since t=3, or 3 hours, you know what time they were380miles apart. The first train was t+1 or 4 hours past 12 p.m. and the second train was t or3 hours past1p.m. TRAIN 1 and TRAIN 2 were 380 miles apart at4p.m. DON"T FORGET TO RATE!!

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