Suppose the quantity demanded per week of a certain dress isrelated to the unit

Question

Suppose the quantity demanded per week of a certain dress isrelated to the unit price p by the demand equation p =700 -x (the square root is all of 700 - x), wherep is in dollars and x is the number of dressesmade. To maximize the revenue, how many dress should be madeand sold each week? Hint
R(x) = px If I could see the work,it work help out, so that I couldtell what I'm doing wrong? Thanks! Suppose the quantity demanded per week of a certain dress isrelated to the unit price p by the demand equation p =700 -x (the square root is all of 700 - x), wherep is in dollars and x is the number of dressesmade. To maximize the revenue, how many dress should be madeand sold each week? Hint
R(x) = px If I could see the work,it work help out, so that I couldtell what I'm doing wrong? Thanks! Thanks!

Explanation / Answer

revenue R(x) = px = x(700-x) to maximize R, you have to calculate dR/dx = 0 (700-x) - x (1/2)/(700-x) = 0 multiplying by (700-x), 700 -x - x/2 = 0 700 = 3x/2 x = 1400/3

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---