A light-rail train going from one station to thenext on a straight section of tr

Question

A light-rail train going from one station to thenext on a straight section of track accelerates from rest at 2.39m/s2 for 17.8 s/ It then proceeds at constant speed for1497 m before slowing down at 2.2 m/s2 until it stops atthe station. What is the distance between thestations?
How much time does it take the train to go betweenthe stations? A light-rail train going from one station to thenext on a straight section of track accelerates from rest at 2.39m/s2 for 17.8 s/ It then proceeds at constant speed for1497 m before slowing down at 2.2 m/s2 until it stops atthe station. What is the distance between thestations?
How much time does it take the train to go betweenthe stations?

Explanation / Answer

For the first part,   d = vo t + 1/2 a t2 , where vo= 0. so,      d = (1/2) ( 2.39m/s2 ) ( 17.8 s )2   =  378.6 m For the second part:   d = 1497 m For the last part:    vo = thevelocity at end of the first segment, which is  vf = vo + a t                                                                                                               vf   = 0   + (2.39 ) (17.8) = 42.54m/s for last segment:    vf2 = vo2 + 2 a d             0(since stops) = (42.54)2 + 2 ( - 2.2m/s2 ) d,    solve for d toget    d = 411.3 m Finally, add the above 3 distances to get total distancebetween stations. total d   = 378.6m + 1497m + 411.3m   = 2286.9m     final answer. PS - this problem is more physics than math.

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