Solve each part Algebrically with variables and detailedAnswer a) Mary\'s age is

Question

Solve each part Algebrically with variables and detailedAnswer
a) Mary's age is 2 / 3 that of Peter's.Two years ago Mary's age was1/2 of what peters age will be in 5 years time. How old ispeter   now?? b)if a piece of wood is 5 cm longer than a second piece, and3/4 of the second piece is equal to 3/5 of the first . what is thelength of the second part? Solve each part Algebrically with variables and detailedAnswer
a) Mary's age is 2 / 3 that of Peter's.Two years ago Mary's age was1/2 of what peters age will be in 5 years time. How old ispeter   now?? b)if a piece of wood is 5 cm longer than a second piece, and3/4 of the second piece is equal to 3/5 of the first . what is thelength of the second part?

Explanation / Answer

wood 2 is 20 cm long wood 1 is 25 cm long 25cm + 20 cm = 45cm So wood 2 has to be 20cm long and the total length of both is45 :) Did I help?

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