I can't figure out how to get an anwer for 5(y-1)=2y+1 Ithink my next step is 5y-5=2y+1 thenmaybe 5y-2y = 3y-5=1 3y-5=1+5 3y=6 3y=6 y=2 Did I work this problem correctly? If not, can someoneshow me how it should be done? I can't figure out how to get an anwer for 5(y-1)=2y+1 Ithink my next step is 5y-5=2y+1 thenmaybe 5y-2y = 3y-5=1 3y-5=1+5 3y=6 3y=6 y=2 Did I work this problem correctly? If not, can someoneshow me how it should be done?
Explanation / Answer
you did do it correcty, first you expanded the brackets to get5y - 5 then you collected like terms whcih was 5y - 2y = 3y and 1 + 5= 6 then you solved for y whcih is y = 6/3 = 2