If Steven can mix 20 drinks in 5 mins. Sue can mix 20 drinks in 10mins, and Jack
ID: 3095303 • Letter: I
Question
If Steven can mix 20 drinks in 5 mins. Sue can mix 20 drinks in 10mins, and Jack can mix 20 drinks in 15 mins. how much time will ittake all 3 of them working together to mix the 20 drinks?NOTE: can someone please explain the procedure for solving theproblem. thanks
A. 2 mins and 44 secs B. 2 mins and 58 secs C. 3 mins and 10 secs D. 3 mins and 26 secs E. 4 mins and 15 secs
NOTE: can someone please explain the procedure for solving theproblem. thanks
A. 2 mins and 44 secs B. 2 mins and 58 secs C. 3 mins and 10 secs D. 3 mins and 26 secs E. 4 mins and 15 secs
Explanation / Answer
First describe a rate of of pouring for each person: 20drinks/(timein minutes*60seconds/minute) Steve=0.067drinks/second Sue=0.033drinks/second Jack=0.022drinks/second Since they are all working at the same time we can add theirpouring rates together. Rate for all three=0.122drinks/second Now we create a simple function: # of Drinks Poured = 0.122drinks/second*time so 20=0.122*t 20/0.122=t 163.94seconds=t doing a quick conversion to minutes: 2 minutes and 44 seconds