I need some help with this problem. Chuck and Dana agree to meet in Chicago for

Question

I need some help with this problem. Chuck and Dana agree to meet in Chicago for the weekend.Chuck travels 84 miles in the same time that Dana travels 78 miles.If Chuck's rate of travel is 3 mph more than Dana's, and theytravel the same length of time, at what speed does Chucktravel? Thanks for the help! I need some help with this problem. Chuck and Dana agree to meet in Chicago for the weekend.Chuck travels 84 miles in the same time that Dana travels 78 miles.If Chuck's rate of travel is 3 mph more than Dana's, and theytravel the same length of time, at what speed does Chucktravel? Thanks for the help!

Explanation / Answer

Let R be Chuck's speed. Let R - 3 be Dana's speed. Distance formula for Chuck: 84 = RT Distance formula for Dana 78 = (R - 3)T Solve each of these for T: T = 84/R T = 78/(R-3) Equate them (which cancels T): 84/R = 78/(R-3) Cross multiply: 84(R-3) = 78(R) 84R - 84*3 = 78R 6R = 84*3 6R = 252 R = 252/6 R = 42 mph Answer: Chuck is driving at 42 mph (for 2 hours) Dana is driving at 39 mph (for 2 hours)

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