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Double check answers Cos(Theta)Csc(theta)=cot (theta) 1+Tan{squared}(theta)/1+co
Double check answers Cos(Theta)Csc(theta)=cot (theta) 1+Tan{squared}(theta)/1+co
ID:
3095760
• Letter:
D
Question
Double check answers Cos(Theta)Csc(theta)=cot (theta) 1+Tan{squared}(theta)/1+cot{squared}(theta)=(1/cos{squared}(theta))/(1/sin{squared}(theta) Tan(theta)+cot(theta)=? 1/(1+sin(theta))+1/(1-sin(theta))=? 2sin(theta)(cot(theta)+tan(theta))=? (sec(theta)-1)/(sec(theta)+1)+(cos(theta)-1)/(cos(theta)+1)=? Sec(theta)+tan(theta)=cos(theta)/1-sin(theta (tan(theta)-sin(theta))/sec(theta)=sin{cubed}(theta)/1+(cos(theta)) tan(theta)+cot(theta)= csc(theta)+sec(theta) Double check answers Cos(Theta)Csc(theta)=cot (theta) 1+Tan{squared}(theta)/1+cot{squared}(theta)=(1/cos{squared}(theta))/(1/sin{squared}(theta) Tan(theta)+cot(theta)=? 1/(1+sin(theta))+1/(1-sin(theta))=? 2sin(theta)(cot(theta)+tan(theta))=? (sec(theta)-1)/(sec(theta)+1)+(cos(theta)-1)/(cos(theta)+1)=? Sec(theta)+tan(theta)=cos(theta)/1-sin(theta (tan(theta)-sin(theta))/sec(theta)=sin{cubed}(theta)/1+(cos(theta)) tan(theta)+cot(theta)= csc(theta)+sec(theta)
Explanation / Answer
I need help getting them to simplest form the ones where they are set equal need to prove how they areequal
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