When John, decided to renovate his garage, he also wanted to attach it to his ho

Question

When John, decided to renovate his garage, he also wanted to attach it to his house. The only one wall that was available to achieve this was the kitchen wall.



The contractor informed him that the area of his new garage will be limited by the cost of the materials he should buy. After some calculations, they decided that he could afford three walls with a total length of 66 feet. The kitchen wall would serve as the fourth wall.



But John had two big cars, so he wanted to build a garage with the biggest possible area under his contractor’s constraints.



•What is the formula for the area of the garage?

Explanation / Answer

afford three walls with a total length of 66 feet To solve this you would think I have to find the biggest area possible. The area of a square is A = s^2 so 66/3 = 22 and 22^2 = 484 ft The area of a rectangle is length*width and since we want the biggest width possible with the most area using 66 feet possible. use process of elimination you find that 66 - 33 = 33 33/2 = 16.5 33 * 16.5 = 544.5 66-34 = 32 32/2 = 16 34*16=544 66-32 = 34 34/2 = 17 32*17=544 So, with the max area with the most width for 2 cars it would be 33 l and 16.5 length making area = 544.5

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