Michaela climbed up a mountain at an average speed of 2 mi/h. She climbed down a
ID: 3103236 • Letter: M
Question
Michaela climbed up a mountain at an average speed of 2 mi/h. She climbed down at an average speed of 4 mi/h. What is Michaela's average speed for the entire trip? Round to the nearest tenth.
Simplify 4z^3-8z^2/z-2. Identify any z-values for which the expression is undefined. Divide 2x^9/9x^8y /4/9y^5. Assume that all expressions are defined. Michaela climbed up a mountain at an average speed of 2 mi/h. She climbed down at an average speed of 4 mi/h. What is Michaela's average speed for the entire trip? Round to the nearest tenth. Identify the asymptotes, domain, and range of the function g(x) = 1/x-3-4 Solve the inequality 3/x+4Explanation / Answer
(4z^3-8z^2)/(z-2) 4 z^2*(z-2)/(z-2) =4z^2 it's undefined at 2. So we can multiply by the opposite. 2x^9*9y^5 ------------ 9x^8y*4 we subtract powers in fractions x*y^4/2 so she went a distance 1 at 2 miles per hour. Therefore it took a half hour. Then on the way back she did it at 4 miles per hour. It took fifteen minutes. 2 miles in 45 minutes = 2*4/3 / .75*4/3 = 8/3 miles per hour