Math 308 Introduction to Problem Solving Pick 2 of the following probl ems to do
ID: 3118976 • Letter: M
Question
Math 308 Introduction to Problem Solving Pick 2 of the following probl ems to do for this introductory homework assignment. Follow the rubric and make sure you include all 5 parts. Do your best. I just want to see what youll do. The final answer, although is mportant, is NOT the most important part. Work each problem on a se te sheet of Don't write on the back of the pages Where Do They Live Alice, Bob, Chuck, David and Elsa live next to each other in a row in five different houses. The houses are numbered 101, 102. 103, 104 and 105 along a street that runs from south to north, with 105 being the farthest north. Alice does not live in 105. Bob does not live in 101. Chuck does not live in either 101 or 105. David lives in a house farther north than Bob, and Elsa does not live in a house adjacent to Chuck. Chuck does not live in a house adjacent to Bob. Identify the occupants of the five houses. The Gambler A gambler took his week's paycheck to a casino. Aside from a $200 daily parking fee which he paid upon arrival and a $100 tip to the dealer each day when he left, there were no other expenses. The first day he lost half the money he had after paying for parking. The exact same thing happened the second and third day. After leaving the casino the third day, he had $39.00 left. How much did he start with? (hint: when he first anrives he pays for parking, then gambles and loses half of what he has, then gives the dealer the tip then starts all over again the next day, 3. How Do you Do? Thirty people are in a room and each person shakes hands exactly once with everyone else. How many handshakes will take place?Explanation / Answer
Assuming that there are n people in the party, hence the 1st person will shake hands with the remaining the (n-1) persons,
Similarly each of the person will shake hand with each other (n-1)
Total Number of Handshakes = number of persons * number of handshakes done by one person
=> n * (n-1)
Now, what is the wrong with this answer?
Let us suppose there are three friends in the party, A, B and C, A shakes hand with B and C so 2 handshakes, B handshakes with A and C, C handshaes with A and B
but A has already shaked hand with B, so each of the number is getting counted twice
Hence the final answer should be n(n-1)/2 = 30 * 29/2 = 435 handshakes