Please assist I have attached the data needed. All answers should be complete se
ID: 3125407 • Letter: P
Question
Please assist I have attached the data needed.
All answers should be complete sentences. We need to find the confidence interval for the SLEEP variable. To do this, we need to find the mean and then find the maximum error. Then we can use a calculator to find the interval, (x-E, x E) First, find the mean. Under that column, in cell E37, type -AVERAGE(E2:E36). Under that in cell E38, type -STDEV(E2:E36). Now we can find the maximum error of the confidence interval. To find the maximum error, we use the "confidence" formula In cell E39, type =CONFIDENCE.NORM(0.05,E38,35). The 0.05 is based on the confidence level of 95%, the E38 is the standard deviation, and 35 is the number in our sample. You then need to calculate the confidence interval by using a calculator to subtract the maximum error from the mean (x-E) and add it to the mean (xtE). in cell E38, type-STDEVE2:E36Now we ca Give and interpret the 95% confidence interval for the hours of sleep a student gets. (S points) I. Then, you can go down to cell E40 and type CONEIDENCENORM0.01,E38,35) to find the maximum error for a 99% confidence interval. Again, you would need to use a calculator to subtract this and add this to the mean to find the actual confidence interval. alculator 1o mtum TI fr mODMO.OL.E3 Give and interpret the 99% confidence interval for the hours of sleep a student gets. (S points) 2. 3. Compare the 95% and 99% confidence intervals for the hours of sleep a student gets. Explain the difference between these intervals and why this difference occurs. (:5 points)Explanation / Answer
1)
95% confidence interval for the average hours of sleep a student gets is ( 6.2236, 7.1479).
We are 95% confident that average hours of sleep of all students gets falls in the interval ( 6.2236, 7.1479).
2).
99% confidence interval for the average hours of sleep a student gets is ( 6.0652, 7.3062).
We are 99% confident that average hours of sleep of all students gets falls in the interval ( 6.0652, 7.3062).
3).
99% confidence interval is wider than 95% confidence interval.
We know that CI=mean ±criticle value*se.
Critical value of the probability distribution ( in this case t distribution) 99% is larger than 95% value.
There fore 99% confidence interval is wider than 95% confidence interval.