In a clinical trial of a drug used to help subjects stop smoking, 917 subjects w
ID: 3130795 • Letter: I
Question
In a clinical trial of a drug used to help subjects stop smoking,
917 subjects were treated with 1 mg doses of the drug. That group consisted of 38
subjects who experienced nausea. The probability of nausea for subjects not receiving the treatment was 0.00980.
Complete parts (a) through (c).
a. Assuming that the drug has no effect, so that the probability of nausea was
0.0098.
find the mean and standard deviation for the numbers of people in groups of
917 that can be expected to experience nausea.The mean is ____ people.
Explanation / Answer
given the probability of nausea was 0.0098. i.e p=0.0098 q = 1-p = 1- 0..0098 = 0.9902
the mean for the numbers of people in groups of 917 that can be expected to experience nausea is
np = 917 X 0.0098 = 8.9866 = 9
variance = npq = 8.9866 X 0.9902 =8.816 = 9
standard deviation = sqrt( varince) = sqrt(npq) = 3