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In a clinical trial of a drug used to help subjects stop smoking, 917 subjects w

ID: 3130795 • Letter: I

Question

In a clinical trial of a drug used to help subjects stop smoking,

917 subjects were treated with 1 mg doses of the drug. That group consisted of 38

subjects who experienced nausea. The probability of nausea for subjects not receiving the treatment was 0.00980.

Complete parts (a) through (c).

a. Assuming that the drug has no effect, so that the probability of nausea was

0.0098.

find the mean and standard deviation for the numbers of people in groups of

917 that can be expected to experience nausea.The mean is ____ people.

Explanation / Answer

given the probability of nausea was 0.0098. i.e p=0.0098 q = 1-p = 1- 0..0098 = 0.9902

the mean for the numbers of people in groups of 917 that can be expected to experience nausea is

np = 917 X 0.0098 = 8.9866 = 9

variance = npq = 8.9866 X 0.9902 =8.816 = 9

standard deviation = sqrt( varince) = sqrt(npq) = 3