The director of admissions at Kinzua University in Nova Scotia estimated the dis
ID: 3133868 • Letter: T
Question
The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall semester on the basis of past experience.
What is the expected number of admissions for the fall semester?
Compute the variance and the standard deviation of the number of admissions. (Round your standard deviation to 2 decimal places.)
The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall semester on the basis of past experience.
What is the expected number of admissions for the fall semester?
The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall semester on the basis of past experience.
Admissions Probability
1,060 0.4
1,260 0.2
1,620 0.4
1.
What is the expected number of admissions for the fall semester?
Expected number of admissions
2.
Compute the variance and the standard deviation of the number of admissions. (Round your standard deviation to 2 decimal places.)
Variance
Standard deviation
The director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall semester on the basis of past experience.
Admissions Probability 1,060 0.4 1,260 0.2 1,620 0.4 1.What is the expected number of admissions for the fall semester?
Expected number of admissions 2.Compute the variance and the standard deviation of the number of admissions. (Round your standard deviation to 2 decimal places.)
Variance Standard deviationThe director of admissions at Kinzua University in Nova Scotia estimated the distribution of student admissions for the fall semester on the basis of past experience.
Explanation / Answer
Given
a) The expected number of admissions for the fall semester is
E(Admissions)= E(X) = 1060*0.4 + 1260*0.2 + 1620*0.4
=1,324
b) To Compute the variance and the standard deviation of the number of admissions,
E(X^2) = 10602*0.4 + 12602*0.2 + 16202*0.4
=1,816,720
Var(X) = E(X2) - [E(X)]2 = 1,816,720 - 1,3242 = 63,744
SD(X) = Sqrt(63744) = 252.48
Admissions Probability 1,060 0.4 1,260 0.2 1,620 0.4