Analyze the data using techniques discussed in class. Use =.05 for conducting hy
ID: 3134163 • Letter: A
Question
Analyze the data using techniques discussed in class. Use =.05 for conducting hypothesis tests. A biologist wished to study the effects of ethanol on sleep time. A random sample of 20 rats, similar with respect to age and other characteristics, was selected, and each rat was given an oral injection having a particular concentration of ethanol per body weight. The rapid eye movement (REM) sleep time for each rat was then recorded for a 24-hour period, with the results shown in the following table:
0 (Control) 1 g/kg 2 g/kg 4 g/kg
88.6 63.0 44.9 31
73.2 53.9 59.5 39.6
91.4 69.2 40.2 45.3
68.0 50.1 56.3 25.2
75.2 71.5 38.7 22.7
Explanation / Answer
Here we need to compare more than 2 populations mean so ANOVA will be used.
Hypotheses are:
H0: The mean rapid eye movement (REM) sleep time is same for each group.
Ha: The mean rapid eye movement (REM) sleep time is not same for each group.
Following is the output of ANOVA generated by the excel:
P-value of the test : 0.000008
Since p-value is less than 0.05 so at 5% level of siginificance we reject the null hypothesis.
Anova: Single Factor SUMMARY Groups Count Sum Average Variance 0(Control) 5 396.4 79.28 103.652 1g/kg 5 307.7 61.54 87.313 2g/kg 5 239.6 47.92 89.512 4g/kg 5 163.8 32.76 91.373 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 5882.3575 3 1960.785833 21.09222357 8.32488E-06 3.238872 Within Groups 1487.4 16 92.9625 Total 7369.7575 19