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Please solve #1. I dont need the answer in matlab format. Handwritten or similar

ID: 3144547 • Letter: P

Question

Please solve #1. I dont need the answer in matlab format. Handwritten or similar is fine. I just want to know the answer. Please make it legible. Thank you

Fil: Ei Vi Windom Helo Home Tools Project bpdfx sanket The second part oi the project doesn't require MAILAB. You will need to submit either a Word file or a PDF file with the answers to the questions asked in the second part. Your work must be mathematically typese the row reduction algorithm. Word has an cquation editor that you can usc to typesct matrices, vectors, and any other mathematical symbols. If you are unfamiliar with the Equation Editor getting used to the typesctting will take some time. Don't wait until the last minute to complcte the project. You will submit your project through the course Canvas page. Submit both the M-file and the Word or PDF file. Do not use any special symbols in name of the M-file and make sure you inelude your name in the body of both file:s Hnd our toola here t no hand calculations scanned into the file. Show me some of the steps in Create PDF Fdit PDF D Export PDIr Comment Organize Pages Enhan Scans O P a till Sign Prepare Furrm Part 1: MATLAB Required 1. Solve the following system: send for signature 2.1.2 613 .. Send & Track 914 , Eh compare iles r2 +33 -2x5-4x6-4 2. Solve the following homogenes system: Subscriptior Expired S bsne nowto restore access to desitop, mobele and weo tools x1-2x2 + 2.3 = 0 10-43 PM E O lype here to search

Explanation / Answer

(1).Solution of system of equation using GaussJordan Elimination

Make the pivot in the 1st column by dividing the 2nd row by 6 and swap the 2nd and the 1st rows

Eliminate the 1st column

Find the pivot in the 2nd column and swap the 4th and the 2nd rows

Eliminate the 2nd column

Make the pivot in the 6th column by dividing the 3rd row by 4/3

Eliminate the 6th column

Solution set:

x1 = -73/8 + (11/2)x3 + (3/2)x4 - (1/2)x5

x2 = 5 - 3x3 + 2x5

x6 = 1/4

x3, x4, x5 = free

X1 X2 X3 X4 X5 X6 b 1 0 2 6 0 -4 -8 8 2 6 11 0 -9 -19 3 1 3 2 4 1 -3 -7 1 2 4 0 1 3 0 -2 -4 4