I only need the answer for(C)and the answer is a simplified fraction. This is a
ID: 3152547 • Letter: I
Question
I only need the answer for(C)and the answer is a simplified fraction. This is a resubmission because of a typing error on my part.
Assume that a company hires employees on Mondays ,Tuesdays, Wednesdays with equal likelihood. Complete parts (a) through (c) below. If two different employees are randomly selected, what is the probability that they were both hired on a Wednesday? (A) & (B) are already answered. A)The probability is__1/9______ (Type an integer or a simplified fraction.) B) If two different employees are randomly selected, what is the probability that they were both hired on the same day of the weekday of the week? The probability is__1/3_____(Type an integer or a simplified fraction.) What is the probability that 6 people in the same department were all hired on the same day of the weekday of the week? Is such an event unlikely? The probability is______ (a simplified fraction.)
Explanation / Answer
probability of hiring on mondays=1/3
probability of hiring 6 people on mondays=1/3*1/3*1/3*1/3*1/3*1/3=(1/3)6
probability of hiring 6 people on tuesdays=1/3*1/3*1/3*1/3*1/3*1/3=(1/3)6
probability of hiring 6 people on wednesdays=1/3*1/3*1/3*1/3*1/3*1/3=(1/3)6
probability of hiring 6 people on same day=probability of hiring 6 people on mondays+probability of hiring 6 people on tuesdays+probability of hiring 6 people on wednesdays=(1/3)6 +(1/3)6 +(1/3)6 =3*(1/3)6 =(1/3)5 =0.0041
such event can be possible. such an event is likely.