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Report the following: State the null (H0) and alternative (H1) hypotheses. Assum

ID: 3156898 • Letter: R

Question

Report the following:

State the null (H0) and alternative (H1) hypotheses.

Assume = 0.05, two-tails; report values for df and rcrit [1 pt] Fill in the missing values in the data table above to show your INITIAL computations

Report values for SPXY SSX SSY and Pearson’s r

State your decision regarding the null hypothesis, H0.

Indicate whether the relationship between X and Y is “negative” or “positive”

Indicate whether the relationship between X and Y is “weak” or “medium” or “strong” according to Cohen’s guidelines for the value of Pearson’s r.

Report the value of the proportion of variability in Y accounted for by X.

Write 1 sentence interpreting the value you computed.

Write 1 sentence demonstrating how the results of this specific hypothesis test would appear in a research report

X Y X2 Y2 XY 2 0 3 1 7 4 5 6 4 6 3 6 X= Y= X2= Y2= XY=

Explanation / Answer

Here we have given data of x and y values.

Report the following:

State the null (H0) and alternative (H1) hypotheses.

Assume = 0.05, two-tails; report values for df and rcrit [1 pt] Fill in the missing values in the data table above to show your INITIAL computations.

Here we have to test he hypothesis that,

H0 : There is no correlation between x and y.

H1 : There is correlation between x and y.

Assume alpha = level of significance = 5% = 0.05

Report values for SPXY SSX SSY and Pearson’s r

The correlation coefficient formula is,

r = n*(xy) - (x)(y) / sqrt [n*x2 - (x)2 ] * [n*y2 - (y)2 ]

= (6*103 - 24*23) / sqrt [6*112 - 242]*[6*125 - 232]

= 66/sqrt(96*221)

= 66/145.66

r = 0.4531

The test statistic is,

t = r*sqrt(n-2) / sqrt(1-r2)

= 0.4531*sqrt(6-2) / sqrt(1-0.45312)

= 0.9062/0.8915

t = 1.017

Now we have to find P-value :

P-value in EXCEL is,

=TDIST(x, deg_freedom,tails)

where x is tests statistic value.

deg_freedom = n-2 = 6-2 = 4

tails = 2

P-value = 0.3668

P-value > alpha

Accept H0 at 5% level of significance.

Conclusion : There is no correlation between x and y.

Report the value of the proportion of variability in Y accounted for by X.

proportion of variability in Y accounted for by X = r2 = 0.45312 = 0.2053

x y x^2 y^2 xy 2 0 4 0 0 3 1 9 1 3 7 4 49 16 28 5 6 25 36 30 4 6 16 36 24 3 6 9 36 18 24 23 112 125 103