I understand that first question concerning magnitude. The second question I hav
ID: 3161984 • Letter: I
Question
I understand that first question concerning magnitude. The second question I have no idea how 6.91 degrees is the answer, I tried everything! I did tan arch of the same componets used to get magnitude but it isnt working!! Help me please! For each of the in the space to the of the write most 2. ot a left question There answer On little number. is no his first attempt, for partial for these questions. he was credit barely and the He took outside to fly it. distracted it 0.900 see By time off had straight he noticed what south happened, he could 1: He it in the distance the copter 1.20 to bring it home, but instead, copter back in a part of trip). the of south. crashed. direction 10.0° After that, made another adjustment sending Cas his When he found it, of west third part the at this point the distracted second it was 0.3 km from of an angle of west 40.0° easily). attempt his part part This to fly his new was distracted again gets of trip). It trip). He then seeing in the distance, he it 0.300 km straight west sent of b 2.1. crashed sent it 0.856 km straight east and 0.331 km straight north (third (after For again, and he found it 1.30 km west and 0.556 km of his home. a) the Case what are the components the second part of the quadcopter's trip b) (0, distraction)? These are given for (2 points) +0.900) km in (x,y) airs. (0, -0.9000 d) (-0.900, 0) km g) (-0.450, -0 m km 7aquExplanation / Answer
2.4)
Let the initital displacement be r1
second displacement , r2 = -0.3 i <----- i = unit vector along East
third displacement , r3 = 0.856 i + 0.331 j <----- j = unit vector along North
So, r1 + r2 + r3 = -1.3i + 0.556 j
So, r1 + ( -0.3 i ) + (0.856 i + 0.331 j) = -1.3i + 0.556 j
So, r1 = -1.856 i + 0.225 j
So, initital distance = sqrt(1.856^2 + 0.225^2) = 1.87 km <---------answer
b)
direction = atan(0.225/1.856)
= 6.91 deg N of W <--------- answer