Particle A of charge 3.15 times 10^-4 C is a the origin, particle B of charge -5
ID: 3162472 • Letter: P
Question
Particle A of charge 3.15 times 10^-4 C is a the origin, particle B of charge -5.82 times 10^4 C is at (4.00 m, 0), and particle c of charge 1.04 times 10^-4 C is at (0, 3.00 m). We wish to find the net electric force on C what is the x component of the electric force exerted by A on C? N What is the y component of the force exerted by A on C? N Find the magnitude of the force exerted by B on C. N Calculate the x component of the force exerted by B on C N Calculate the y component of the force exerted by B on C N Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. Similarly, find the y component of the resultant force vector acting on C. Find the magnitude and direction of the resultant electric force acting on C. magnitude N direction degree counterclockwise from the X-axis.Explanation / Answer
Here,
qB =- 5.82 *10^-4 C at ( 4, 0)
qC = 1.04 *10^-4 C at ( 0 , 3)
qA = 3.15 *10^-4 C (0 , 0)
a)
for the x component of force of A on C
x component of force of A on C = 0 N
b) for the y component
y component of force of A on C = k * qA * AC/d^2
y component of force of A on C = 9 *10^9 * 3.15 *10^-4 * 1.04 *10^-4/3^2
y component of force of A on C = 32.8 N
c) for the force by B on C
force by B on C = 9 *10^9 * 1.04 *10^-4 * 5.82 *10^-4/(3^2 + 4^2)
force by B on C = 21.8 N
d) for the angle of force on C due to B
theta = arctan(3/4) = 36.9 degree
x component of the force by B on C = 21.8 * cos(36.9)
x component of the force by B on C = 17.44 N
e) for the y component
y component of the force by B on C = 21.8 * sin(36.9)
y component of the force by B on C = 6.53 N