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Question #1 A personnel psychologist studying adjustment to the job of new emplo

ID: 3170597 • Letter: Q

Question

Question #1 A personnel psychologist studying adjustment to the job of new employees found that employees' amount of education (in number of years) predicts ratings by job supervisors two months later. The regression constant in the linear prediction rule for predicting job ratings from education is 0.5 and the regression coefficient is 40. (a) indicate the predictor variable (b) indicate the criterion variable (c) Write the linear prediction rule for this example (dy Indicate the predicted job rating for employees with each of the following amount of education (in (i) 8 (i) 10 (iii) 17 (iv) 19 (v) 21 Question #2 A clinical psychologist has found that scores on a new depression scale predict satisfaction with psychotherapy. The regression constant in the linear prediction rule for predicting satisfaction from the depression score is 12 and the regression coefficient is -0.4. (a) Indicate the predictor variable (b) Indicate the criterion variable

Explanation / Answer

Question # 1

(a) Predictor variable : Employees amount of eduction in yearss

(b) Criterion variable : Rating by job supervisor

(c) Linear prediction rule :

Criterion Variable = regression constant + regresion coefficient x Predictor variable

Job Ratings for employees by supervisor = 0.5 + 0.40 x Employees amount of education in years

(d) Indicate Job Ratings for employees with each of the following Employees amount of education in years

(i) 8 ; Substitute this value as Employees amount of education in the regression equation

Job Ratings for employees by supervisor = 0.5 + 0.40 x Employees amount of education in years

Job Ratings for employees by supervisor =0.5 +0.4 x 8 = 0.5 + 3.2 = 3.7

(ii) 10 ; Substitute this value as Employees amount of education in the regression equation

Job Ratings for employees by supervisor = 0.5 + 0.40 x Employees amount of education in years

Job Ratings for employees by supervisor =0.5 +0.4 x 10 = 0.5 + 4 = 4.5

(iii) 17 ; Substitute this value as Employees amount of education in the regression equation

Job Ratings for employees by supervisor = 0.5 + 0.40 x Employees amount of education in years

Job Ratings for employees by supervisor =0.5 +0.4 x 17 = 0.5 + 6.8 = 7.3

(iv) 19 ; Substitute this value as Employees amount of education in the regression equation

Job Ratings for employees by supervisor = 0.5 + 0.40 x Employees amount of education in years

Job Ratings for employees by supervisor =0.5 +0.4 x 19 = 0.5 + 7.6 = 8.1

(v) 21; Substitute this value as Employees amount of education in the regression equation

Job Ratings for employees by supervisor = 0.5 + 0.40 x Employees amount of education in years

Job Ratings for employees by supervisor =0.5 +0.4 x 21 = 0.5 + 8.4 = 8.9