Can someone help me with this and uplaod file to dropbox? In this exercise you w
ID: 3174059 • Letter: C
Question
Can someone help me with this and uplaod file to dropbox?
In this exercise you will compare the efficiency of the mean of a sample to three other estimators of position of a continuous distribution in one coordinate All three of the alternative estimators have the advantage of being more robust than the mean. N.B. Pay careful attention to the questions asked below as well as to the construction of the spreadsheet. Enter answers to the questions in some prominent place in the workbook. a) Using Excel, in one row generate ten Gaussian distributed random deviates with mean 0 and b) In the same row compute the mean of the ten deviates c) In tho samc row computc thc mcdian of thc tcn dcwiatcs. d) In the same row compute the "truncated mean" obtained by discarding the smallest and largest deviates and computing the mean of the remaining cight e) In the same row compute the "double-truncated mean" (the Instructor just invented this term) by discarding the two smallest and the two largest deviates and computing the mean of the remaining six. (Hint: The Instructor applied the RANK function to each of the deviates ten more cells to determine which of them should be discarded. f) Replicate the row created in steps a)-e) about 3000 times. g) For each of the four estimators compute the mean of the sample of 3000 (should be close to Zero h) For each of the four estimators compute the root mean square (RMS) about zero. (SUMPRODUCT anyone?) i) For each of the four estimators use Excel's STDEV.S function to compute the standard deviation. How do these values compare with the results of h)?Explanation / Answer
Link :
https://www.dropbox.com/s/euftqjo9qs6upjn/Mean.xlsx?dl=0
Rank Sample of 10 Gaussian RV 1 -1.559665179 2 -1.414236976 3 -0.89406285 4 -0.508239282 5 0.005852598 6 0.232608954 7 0.730071861 8 1.112891823 9 1.136943411 10 1.169973984 Mean 0.001213834 Median 0.119230776 Truncated mean 0.050228692 Double truncated mean 0.113187184