Question
Condi ionH Probability tha a is carrying a visa Catd .60, Prvu & AmEx is 20, Pciu. Probab that a person carries ixath is 15 Calvulale the probability that a perHIrlL wiu carTV at least susie the carl-- use the matrix notation Joint Probabilities, conditional probabilities (show them clearly) Marginal L P (a random person dnesn't have buuh of the cards ii. P (a person has visa cardr also visa) iii. Give thnt a person has Amer ard, calculate the Puhe has (Draw Tree Diugram also shows enndiional probahilitles) iv. Probability that a random person will carry at least one of the curds
Explanation / Answer
(i) probabilty that a person have at least one card =P(VUA) =P(V)+P(A)-P(A V) =0.6+0.2-0.15=0.65
hence probability does not have both of the cards =1-P(VUA)=1-0.65=0.35
(ii) P(V)=0.6
(iii)P(V|A) =P(V&A)/P(A)=0.15/0.2=0.75
(iv) probabilty that a person have at least one card =P(VUA) =P(V)+P(A)-P(A V) =0.6+0.2-0.15=0.65