Please use data below. 5.12 exercise 25 Using FX CG10, How do you compute the co

Question

Please use data below. 5.12 exercise 25

Using FX CG10, How do you compute the covariance.

See question A. How do you get 958.429?

which numbers did you use for Xi and Yi?

P Study P Statistics llsboth coclo Close 5.1 Online Exercises objective: Compute covariances and coefficie 25 of61 (3 complete) v correct (X Section 5.12 Exercise 25 The following di the Rt. in ga iced coffoc und lo thu decimal heeded. G.G b. Comput etticlent of 25.8 22.6 Which do ationship betwe plai Plate Pal gth of rdat ngth of aluabl eptble to the negati rking veri A. The covariance shows ry strong negativa ralationship. It calorie& MD. The comdation indicatos a moderate postive relationship. /s calori:s rly perfect posi tionship. and fat. Question iscomplote. Tab cn cred ndicator to sac correct a All parts Similar Questicn n thing F Word (Product Activati Failed The covariance measures the strength of the linear relationship between two variables. Use technology or the formula below to compute the covariance, where X is the sample mean for X, Y is the sample mean for Y Xi is the ith value of X Yi is the ith value of Y, and n is the sample size.

Explanation / Answer

Xi represent - calories

Yi represens - Fat

mean of X (calories ) = 445.714

mean of Y (Fat) = 18.286

N = 7

calculating by given formula we will get required value.

cov(X,Y) = 981.21428

Sum(X) =250 + 270 + 410 + 520 + 530 + 540 + 600 = 3120
XMean = 445.714
Sum(Y) =6.7 + 6.6 + 25.8 + 32.7 + 17.2 + 20.3 + 22.6 = 131.9
YMean = 18.843
Covariance(X,Y) = SUM(xi - xmean)*(yi - ymean)/(samplesize -1)
= (250-445.714)*(6.7-18.843)+(270-445.714)*(6.6-18.843)+(410-445.714)*(25.8-18.843)+(520-445.714)*(32.7-18.843)+(530-445.714)*(17.2-18.843)+(540-445.714)*(20.3-18.843)+(600-445.714)*(22.6-18.843))/6
= 981.214

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