An urn contains 8 marbles; there is 1 red marble, 2 green marbles and 5 blue mar

Question

An urn contains 8 marbles; there is 1 red marble, 2 green marbles and 5 blue marbles. You draw two marbles without replacing the first marble before drawing the second marble. Find the probability that the first marble is blue and the second marble is green An urn contains 8 marbles; there is 1 red marble, 2 green marbles and 5 blue marbles. You draw two marbles without replacing the first marble before drawing the second marble. Find the probability that the first marble is blue and the second marble is green

Explanation / Answer

total marbles = 8

probability that the first marble is blue and the second marble is green = P(first marble is blue) * P(second marble is green)

                                                                                          = 5/8 * 2/7

                                                                                          = 5/28 or 0.1786

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---