Please let me know if this make sense in probability: Predictions made in sports
ID: 3182892 • Letter: P
Question
Please let me know if this make sense in probability:
Predictions made in sports are based on the statistical analysis of the past performance of the different teams. Taking this into account, I would expect that a very high ratio of sports articles would start using the weighted random generator in their calculations, most especially at the beginning of the competition.
All sports generate numbers that are inherently random. For instance, baseball and sucker sport games generate home runs, goals, sacks, passes, shots, hits, misses, errors, and many more. Let’s say that a batter has the chance to reach base, dice roll between 1, 2, 3, 4, 5, and 6 times is predicted as follow:
Roll that reach base one time. The sample space is S = {1, 2, 3, 4, 5, 6}.
We need to follow the probabilities.
P (roll a four)
P(roll a four) =
The probability of rolling a four is .
P (roll an odd number)
The event roll an odd number is E = {1, 3, 5}.
P(roll an odd number) =
The probability of rolling an odd number is .
P (roll a number less than five)
The event rolls a number less than five is F = {1, 2, 3, 4}.
The probability of rolling a number less than five is .
The rules of the particular sport, as well as the skill of the participants, introduces bias toward certain values; hence, sports matches are weighted random number generators. A good guess would probably be an 80% of the articles, so that you will not be neither too aggressive nor too conservative.
A WEIGHTEDRANDOM NUMBER GENERATOR JUST PRODUCED A NEW BATCH OF NUMBERS. LETS USE THEM TO BUILD NARRATIVES! All SPORTS COMMENTARYExplanation / Answer
Rolling a die one time,
sample space s={1,2,3,4,5,6}
n(s)=6
Let x be the the event rolling 4.
x={4}
n(x)=1
P(roll a four)=n(x)/n(s)
=1/6
The probability of rolling a four is 1/6 or 0.1667.
The event roll an odd number is E = {1, 3, 5}.
n(E)=3
P(roll an odd number) =n(E) /n(s)
=3/6
=1/2
The probability of rolling an odd number is 1/2 or 0.5.
The event rolls a number less than five is F = {1, 2, 3, 4}.
n(F)=4
P (roll a number less than five) =n(F) /n(s)
=4/6
=2/3
The probability of rolling a number less than five is 2/3 or 0.667.