Consider the differential equation dy/dx = y^3 (x+1) with y(-2)=3. Use euler\'s
ID: 3191391 • Letter: C
Question
Consider the differential equation dy/dx = y^3 (x+1) with y(-2)=3. Use euler's method with dx=0.25 to calculate the first three approximations. What value of x did your y-value approximate? how could you come up with a more accurate prediction? I got the first three approximations as y1 = -3.75, y2= 6.1377 and y3= -22.7643. Are those correct? How do I calculate the value of that the y-value approximates? I tried it and got 1.6641 the first time and -36/7 the second time. I am doing some thing wrong here, how do i do this?Explanation / Answer
you are actually making mistakes in calculating the approximation in the euler's theorem of approximation.