A deck of 52 cards, choose 3, display the cards in order in which you choose the
ID: 3202014 • Letter: A
Question
A deck of 52 cards, choose 3, display the cards in order in which you choose them. Total # of possible outcomes = Total ft of license plates with 3 letters followed by 4 digits = # of ways of choosing a starting lineup (5 players on a basketball team) among 12 players = A baseball team as 12 players, where: - 3 are pure centers - 4 are pure forwards - 4 are pure guards - 1 is a swingman who can play either guard or forward # of ways if choosing a lineup with (1 center, 2 forwards, 2 guards) = # of ways to form a 5-digit binary sequence = # of ways to form a 5-digit binary code with exactly 3 zeroes =Explanation / Answer
1)Here n=52 and c=3
Hence the total no of outcomes is 52C3=(52!/((52-3)!×3!)
=22100
3)total no of playes is 12
And we choose 5 of them
No of ways are 12C5=(12!)/((12-5)!×5!=792
4)total no playes are 12
Now from 3 center we want to select 1
Hence 3C1=3
From 4 forwards and 1 swingman we want to select 2 =5C2=10
Again from 4 guard and 1 swing guard we want to select 2=5C2=10
No of ways we choose the team is=3C1×5C2×5C2=3×10×10
=300