Please answer both parts a and b for the question showing all the steps to solve
ID: 3202465 • Letter: P
Question
Please answer both parts a and b for the question showing all the steps to solve. Thanks in advance.
4. The questions below are based on the following statistics. I10 ptsl Total LGCC GCC Students LGCC Students Students who ride E Train who de #7 train other Means 1090 Men 540 450 660 615 Women 2150 875 a) What is the probability that a student selected at random is a man or a person who rides the E train to school? b) What is the probability that a student selected at random is a woman who does not ride the No. 7 train to school?Explanation / Answer
Total number of students = 1090 + 2150 = 3240
Total number of man students = 1090
Probability of selecting a man P(M) = 1090/3240 = 0.3364
Total number of students who ride to school in train E = 450 + 875 = 1325
Probability of selecting a student who ride to school in train E, P(Te) = 1325/3240 = 0.409
Probability of selecting a man student who ride to school in train E, P(M intersection Te) = 450/3240 = 0.1389
(A) required probability, P(M U Te) = P(M) + P(Te) - P(M intersection Te) = 0.3364 + 0.409 - 0.1389 = 0.6065