Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Problem 6. Among Romulans, there is a trait known as Reas Romulus Betta; Romulan

ID: 3203251 • Letter: P

Question

 Problem 6. Among Romulans, there is a trait known as Reas Romulus Betta; Romulans with this trait enjoy watching Romulan Fish produce flourescent skin colors.  Those who don't have Reas Romulus Betta do not watch these fish.  You are performing a study with a large population of subjects.  The proportions of individuals with phenotype-pairs is as follows:  The proportion of individuals who are   male and        have Reas Romulus Betta is 0.0104;  The proportion of individuals who are female and        have Reas Romulus Betta is 0.417;  The proportion of individuals who are   male and do not have Reas Romulus Betta is 0.386;  The proportion of individuals who are female and do not have Reas Romulus Betta is 0.187.  Question A. What is the probability a Romulan is female in this population?  Question B. What is the probability a Romulan does not have Reas Romulus Betta and is female?  Question C. What is the probability a Romulan does not have Reas Romulus Betta given that she is female? 

Explanation / Answer

P(RA) = Romulan with read romulan betta

P(F) = Probability of female

P(RB) = Romulan without read romulan betta

P(M) = Probability of male

a) Probability of romiulan female = P(F|RA) + P(F|RB)

= 0. 417+ 0.187

= 0.604

b) Probability not have reas romulan betta and female = P(F|RB) = 0.187

c) P(RB|F) = [P(F|RB) * P(RB)] / [P((F|RB) * P(RB) + P(F|RA) * P(RA)]

P(RA) = 0.0104+ 0.417 = 0.4274

P(RB) = 0.386 + 0.187= 0.573

P(F|RB) = 0.187

P(F|RA) = 0.417

= (0.187 * 0.573 ) / (0.187 * 0.573 + 0.417 * 0.4274)

= 0.375