Consider the word \"ANAGRAMMATIST\". How many different anagrams of the word can

Question

Consider the word "ANAGRAMMATIST". How many different anagrams of the word can be made (irrespective of the fact that those anagrams are actual English words)? In an urn there are n balls with n different numbers printed on them and m of them are extracted in a sequence without replacement. For n = m = 3, what is the probability of extracting all 3 of them in ascending order? For n = 10 and m = 10, what is the probability of extracting all 10 of them in ascending order? For n = 10 and m = 5, what is the probability of extracting all 5 of them in ascending order?

Explanation / Answer

1.3

a) ANAGRAMMATIST has

So, from a total of 12 alphabets:

A - 4
M - 2
T - 2
R,G,I,S - 1

Total analgrams posssible is way of ordering these 12 alphabets taking care of repetitons. So, 12!/4!*2!*2! = 4989600

So, you can have 4,989,600 combinations/anagrams for this word

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