I need question c & d please and correction for a & b a)0.351 b) 0.222 (2, 2 pts
ID: 3205308 • Letter: I
Question
I need question c & d please and correction for a & b
a)0.351
b) 0.222
(2, 2 pts ea) The following data comes from the National Cancer Institute (www.cancer.gov). The number of cancer cases estimated for 2008 for the 12 most common cancers (not including non-melanoma skin cancer) are given here Estimated Estimated Cancer Type New Cases Deaths Bladder 68,810 14,100 184450 40930 Breast 148,810 Colon and Rectal 49,960 7,470 40,100 Endometrial 11,059 Kidney (Renal Cell) Cancer 46,232 44,270 Leukemia (All) 21,710 Lung (Including Bronchus) 215.020 161,840 62,480 Melanoma 8,420 Non-Hodgkin Lymphoma 19,160 66,120 34,290 37,680 Pancreatic Prostate 186,320 28,660 1,590 Thyroid 37,340 (a) What is the overall probability that a person that has prob any one of these cancers will die? (round to nearest 0.001) (b) What is the probability that a person that has prob breast cancer will die? (round to nearest 0.001) (c) is the probability of dying if you are diagnosed with breast cancer independent of the probability of dying from cancer if diagnosed with cancer? (demonstrate why or why not with a mathematical calculation) (d) What does your answer to (c) mean in plain non-technical language?Explanation / Answer
(a) probability of death = sum of deaths/total number of cancer patients = 399189/1137632 =0.35
(b)Probabilty that a breast cancer patient dies = 49960/148810 = 0.33573 = 0.336
(c)Answer is no: Since pfor independant events P(A intersection B) = P(A)P(B)
but P(A intersection B)= P(B)
where A is the event of dying of cancer patients
B is the event of dying due to breast cancer
Hence they are not independant
(d)People dieing due to braest cancer and people dying due to cancer are non independent events