A quality manager for Lockheed Corporation monitors the diameters of a particula
ID: 3206467 • Letter: A
Question
A quality manager for Lockheed Corporation monitors the diameters of a particular aircraft part. The graph below represents the diameters (in inches) of a random sample of 70 parts. Stem-and-leaf of Diameters N = 70 Leaf Unit = 0.010 _____ The value of the median in the stem-and-leaf plot is (A) 9.97 (B) 997 (C) 99.7 (D) 35.5 _____ The shape of the distribution in the stem-and-leaf plot is (A) skewed-right (B) bimodal (C) skewed-left (D) more or less symmetric How does the mean compare to the median for the Diameters data? (No computation necessary.) (A) mean is smaller (B) mean is larger (C) roughly equal (D) exactly equal The data value corresponding to the bold, underlined number in the stem-and-leaf plot is (A) 10.22 (B) 1022 (C) 102.2 (D) 2 _____ The value of ???? in the stem and leaf plot is (A) 13 (B) (13) (C) 30 (D) (30) _____ Which one of the following is a reasonable alternative to the stem-and-leaf plot above? (A) pie chart (B) cross-classification table (C) histogram (D) bar chartExplanation / Answer
11)
mean = sum of total data / number of total data
from the stem and leaf plot the sum of all the diameters is 6979
hence mean = 69.79 / 70 = 9.97
12)
As the top 5 have 40 data and the later 5 have 30 data hence it can be called a sskewed left
13) mean = 9.97
median = 9.97
hence they are same
14) 1022 * 0.01 = 10.22
15) (13)
16)
bar chart