For sales promotion, a manufacturer places winning symbols under the caps of 10%

Question

For sales promotion, a manufacturer places winning symbols under the caps of 10% of all Pepsi bottles. Assume winning symbols are placed independently. You buy an eight-pack. Answer the following questions. What is the Probability that there will be no winning symbol under a cap of randomly selected bottle produced by this manufacturer? 0.1 0.9 None of the above What is the Probability that you will not win at all? 0.43 0.9 0.57 None of the above What is the Probability that you will win at least once? 0.1 0.43 0.57 None of the above

Explanation / Answer

p = 0.1

n = 8

P(x) = 8Cx * 0.1x * (1 - 0.1)8-x

4) P(no winning symbol) = 1 - P(winning symbol)

                                        = 1 - 0.1

                                        = 0.9

Option-B) 0.9

5) P(X = 0) = 8C0 * 0.10 * 0.98

                   = 0.43

Option-A) 0.43

6) P(X > 1) = 1 - P(X = 0)

                  = 1 - 0.43

                  = 0.57

Option-C) 0.57

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