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In preparation for the coming season, a bass fisherman decides to buy 5 random l

ID: 3206668 • Letter: I

Question

In preparation for the coming season, a bass fisherman decides to buy 5 random lures out of the 10 new ones in the local tackle shop.

Fill in the blank.

Suppose that 1 of the 10 lures is a Crazy Crawler. The probability that the fisherman will not select this lure is . (Give answer to one decimal place.)
In preparation for the coming season, a bass fisherman decides to buy 5 random lures out of the 10 new ones in the local tackle shop.

Fill in the blank.

Suppose that 1 of the 10 lures is a Crazy Crawler. The probability that the fisherman will not select this lure is . (Give answer to one decimal place.)
In preparation for the coming season, a bass fisherman decides to buy 5 random lures out of the 10 new ones in the local tackle shop.

Fill in the blank.

Suppose that 1 of the 10 lures is a Crazy Crawler. The probability that the fisherman will not select this lure is . (Give answer to one decimal place.)
In preparation for the coming season, a bass fisherman decides to buy 5 random lures out of the 10 new ones in the local tackle shop.

Fill in the blank.

Suppose that 1 of the 10 lures is a Crazy Crawler. The probability that the fisherman will not select this lure is . (Give answer to one decimal place.)
In preparation for the coming season, a bass fisherman decides to buy 5 random lures out of the 10 new ones in the local tackle shop.

Fill in the blank.

Suppose that 1 of the 10 lures is a Crazy Crawler. The probability that the fisherman will not select this lure is . (Give answer to one decimal place.)

Explanation / Answer

Solution:

Total number of lures = 10

Total number of Crazy Crawler = 1

Probability of Crazy Crawler = 1/10 = 0.10

Probability of not selecting Crazy Crawler = 1 – 0.10 = 0.90

Now, we have to find the probability that the fisherman will not select Crazy Crawler which is given as below:

Required probability = nCx*p^x*q^(n – x)

Where, n = 10, x= 5, p = 0.90, q = 1 – p = 1 – 0.90 = 0.10

Required probability = 10C5*0.90^5*0.10^(10 – 5)

Required probability = 252*0.90^5*0.10^5

Required probability = 252* 0.59049* 0.00001

Required probability = 0.001488