An occupational psychologist wishes to assess two different methods of manager s

Question

An occupational psychologist wishes to assess two different methods of manager supervision in influencing employee productivity. One method involves constant supervision by the workplace manager, while the second method involves intermittent (every 15 minutes) supervision by the workplace supervisor. To test whether constant versus intermittent supervision may influence workplace productivity differently, the psychologist first randomly selects 8 employees at his/her organization. Over the course of two weeks, each of the n = 8 employees is exposed to each of the two different supervision conditions. To control for any order effects, half of the participants were randomly assigned to receive constant supervision first, whereas the other half were randomly assigned to receive intermittent supervision first. After each week of supervision, the psychologist measures the productivity of each employee using a Productivity Scale. The scale ranges from a score of 0-35 (where higher numbers indicate higher levels of productivity). Below are results from the experiment in table format: a) State the Independent Variable in this research study, including its levels. b) State the Dependent Variable in this research study. c) What is the appropriate hypothesis test to conduct based on this research design? d) State the null and alternate hypotheses. e) Calculate the appropriate test statistic. f) Determine the critical region for this test at alpha = 0.01. g) What is the correct decision with respect to your hypotheses? Provide ONE reason why. h) Calculate ONE measure of effect size (r^2, d, OR a confidence interval) I) Interpret (in words) the result of this hypothesis test, including proper statistical notation.

Explanation / Answer

Part-a

Independent variable is supervision with two levels :cosnant/intermittent

Part-b

Dependent variable is productivity scale with sores from 0-35

Part-c

Paired sample t-test will be used as same set of subjects is used in both supervision methods.

Part-d

Null hypothesis H0: µd=0 versus the alternative Ha: µd0

Part-e

We have xbar=Sum(d)/n=63/8 = 7.875

Standard deviation s=sqrt((Sum(D2)-Sum(D)2/n)/(n-1)) = sqrt((667-63*63/8)/(8-1))=4.94

Test statistic t=(xbar-0)/(s/sqrt(n)) =(7.875-0)/(4.94/sqrt(8)) =4.51

Part-f

For alpha=0.01 and degree of freedom =n-1=8-1=7 , critical =±3.4995

We reject the null hypothesis if calculated t<-3.4995 or t>3.4995

Part-g

As calculated t=4.51>3.4995, we reject the null hypothesis .

Part-h

Effect size d=xbar/s =7.875/4.94 =1.59

Part-i

We have enough evidence to reject the null hypothesis, t(7)=4.51, critical t0.01/2(7)=3.4995. Hence we conclude that here is significant difference in productivity for constant and intermittent supervision.

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