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Please answer the questions in bold based on the table above the questions. Stat

ID: 3227862 • Letter: P

Question

Please answer the questions in bold based on the table above the questions.

Statistics

HEIGHT: standing height of the child (cm)

N

Valid

1491

Missing

114

Mean

74.7349

Std. Error of Mean

.27226

Median

74.1000

Mode

70.00

Std. Deviation

10.51309

Variance

110.525

Range

67.40

Minimum

33.90

Maximum

101.30

Sum

111429.75

Percentiles

25

67.8000

50

74.1000

75

82.0000

What do you notice about the Mean and the Median?

What does this tell you about the distribution of children’s heights?

2)

Statistics

SICKDAYS:number of child sick days in past fortnight

N

Valid

1605

Missing

0

Mean

1.78

Std. Error of Mean

.049

Median

1.00

Mode

0

Std. Deviation

1.955

Variance

3.823

Range

10

Minimum

0

Maximum

10

Sum

2863

Percentiles

25

.00

50

1.00

75

3.00

What do you notice about the Mean and the Median?

What does this tell you about the distribution of number of sick days

3)

ANOVAa

Model

Sum of Squares

df

Mean Square

F

Sig.

1

Regression

40.645

1

40.645

239.646

.000b

Residual

124.321

733

.170

Total

164.966

734

a. Dependent Variable: sex

b. Predictors: (Constant), weight in kgs

Looking at the ANOVA above

What is the value of the F-Ratio? …………..

What are your conclusions about the model based on this table?

Statistics

HEIGHT: standing height of the child (cm)

N

Valid

1491

Missing

114

Mean

74.7349

Std. Error of Mean

.27226

Median

74.1000

Mode

70.00

Std. Deviation

10.51309

Variance

110.525

Range

67.40

Minimum

33.90

Maximum

101.30

Sum

111429.75

Percentiles

25

67.8000

50

74.1000

75

82.0000

Explanation / Answer

Q.1 Here we see that mean and median are realtively close and median is less than mean here but difference in not so large . As size of the sample is 1400 so approximately we can assume that sample is approximatly normally distributed with right skewness because median value is less than mode.

Q.2 Here difference between mean and median quite large and as Mode is equal to Zero. We can see that the distribution can be a exponential distribution. The freuency values are decreasing in nature so that means it shows an negative exponential nature of distribution.

Q.3 F- ratio for the given ANOVA = 239.646

from this value we can conclude that the model here is extremly significant in nature. In other words we can say that effects of independent variable on dependent variable are real in nature.