Please answer the questions in bold based on the table above the questions. Stat
ID: 3227862 • Letter: P
Question
Please answer the questions in bold based on the table above the questions.
Statistics
HEIGHT: standing height of the child (cm)
N
Valid
1491
Missing
114
Mean
74.7349
Std. Error of Mean
.27226
Median
74.1000
Mode
70.00
Std. Deviation
10.51309
Variance
110.525
Range
67.40
Minimum
33.90
Maximum
101.30
Sum
111429.75
Percentiles
25
67.8000
50
74.1000
75
82.0000
What do you notice about the Mean and the Median?
What does this tell you about the distribution of children’s heights?
2)
Statistics
SICKDAYS:number of child sick days in past fortnight
N
Valid
1605
Missing
0
Mean
1.78
Std. Error of Mean
.049
Median
1.00
Mode
0
Std. Deviation
1.955
Variance
3.823
Range
10
Minimum
0
Maximum
10
Sum
2863
Percentiles
25
.00
50
1.00
75
3.00
What do you notice about the Mean and the Median?
What does this tell you about the distribution of number of sick days
3)
ANOVAa
Model
Sum of Squares
df
Mean Square
F
Sig.
1
Regression
40.645
1
40.645
239.646
.000b
Residual
124.321
733
.170
Total
164.966
734
a. Dependent Variable: sex
b. Predictors: (Constant), weight in kgs
Looking at the ANOVA above
What is the value of the F-Ratio? …………..
What are your conclusions about the model based on this table?
Statistics
HEIGHT: standing height of the child (cm)
N
Valid
1491
Missing
114
Mean
74.7349
Std. Error of Mean
.27226
Median
74.1000
Mode
70.00
Std. Deviation
10.51309
Variance
110.525
Range
67.40
Minimum
33.90
Maximum
101.30
Sum
111429.75
Percentiles
25
67.8000
50
74.1000
75
82.0000
Explanation / Answer
Q.1 Here we see that mean and median are realtively close and median is less than mean here but difference in not so large . As size of the sample is 1400 so approximately we can assume that sample is approximatly normally distributed with right skewness because median value is less than mode.
Q.2 Here difference between mean and median quite large and as Mode is equal to Zero. We can see that the distribution can be a exponential distribution. The freuency values are decreasing in nature so that means it shows an negative exponential nature of distribution.
Q.3 F- ratio for the given ANOVA = 239.646
from this value we can conclude that the model here is extremly significant in nature. In other words we can say that effects of independent variable on dependent variable are real in nature.