For the last question it reads this: Since the P-value is (less or greater) than
ID: 3228722 • Letter: F
Question
For the last question it reads this: Since the P-value is (less or greater) than the significance level, (reject or fail to reject) the null hypothesis. There (is or is not) sufficient evidence to support the claim of a difference in measurements between the two arms.
Listed below are systolic blood pressure measurements (mm Hg) taken from the right and left arms of the same woman. Assume that the paired sample data is a simple random sample and that the differences have a distribution that is approximately normal. Use a 0.01 significance level to test for a difference between the measurements from the two arms. What can be concluded? Right arm 146 144 136 136 139 Left arm 185 174 180 145 138 In this example, Hd s the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the measurement from the right arm minus the measurement from the left arm. What are the null and alternative hypotheses for the hypothesis test? O A. Ho: d 0 O B. Ho: Hd 0 H1: d 0 Hd 0 O C O D. Ho: d 30 0- Hd 1: d 0 H1: Hd 0 Identify the test statistic. t Round to two decimal places as needed.) dentify the P-value P-value Round to three decimal places as needed.) What is the conclusion based on the hypothesis test? Since the P-value is Y than the significance level Y the null hypothesis. There Y sufficient evidence to support the claim of a difference in measurements between the two arms.Explanation / Answer
The statistical software output for this problem is:
Paired T hypothesis test:
D = 1 - 2 : Mean of the difference between Right Arm and Left Arm
H0 : D = 0
HA : D 0
Hypothesis test results:
Hence,
Option D
t = -2.78
P - value = 0.05
Conclusion: Greater; Fail to reject; is not
Difference Mean Std. Err. DF T-Stat P-value Right Arm - Left Arm -24.2 8.691375 4 -2.7843696 0.0496