A box contains 10 resistors, 6 diodes and 4 capacitors. 2 parts are taken from t

Question

A box contains 10 resistors, 6 diodes and 4 capacitors. 2 parts are taken from the box. Consider the following events: A) the first part is resistor B) the first part is diode C) the first part is capacitor D) the second part is resistor E) the second part is diode F) the second part is capacitor Find the following probabilities a) p(A) =? b) p(B) =? c) p(C) =? d) p(D/A)=? e) p (D/B)= ? f) p(D/C) =? g) p(E/A)=? h) p (E/B) =? i) p(E/C)=? j) p(F/A =? k) p(F/B)=? l) p(F/C=? Find probabilities to take a) 2 resistors b) 2 diodes c) one diode and one capacitor We have taken 2 parts from the box. What are probabilities that we have taken a) at least one resistor b) at least one diode c) at least one capacitor

Explanation / Answer

Ans:10 resistors,6 diodes,4 capacitors

2a) 10C2/20C2=10*9/20*19

b) 6C2/20C2=6*5/20*19

c) (6C1*4C1)/20C2=6*4*2/20*19

3a) P(atleast one resistor)=P(one resistor and one diode or capacitor)+P(2 resitor)=(10C1*10C1)/20C2+ (10C2)/20C2

b)  P(atleast one diode)=P(one diode and one resistor or capacitor)+P(2 diodes)=(6C1*14C1)/20C2+ (6C2)/20C2

c)P(atleast one capacitor)=P(one capacitor and one diode or resistor)+P(2 capacitors)=(4C1*16C1)/20C2+ (4C2)/20C2

1)a) 10/20

b)6/20

c)4/20

d)10*9/20*19

e)6*10/20*19

f)4*10/20*19

g)10*6/20*19

h)6*5/20*19

i)4*6/20*19

j)10*4/20*19

k)6*4/20*19

l)4*3/20*19

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