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Please answer the question legible 1. 20 points An urn initially contains one re

ID: 3241805 • Letter: P

Question


Please answer the question legible

1. 20 points An urn initially contains one red and one blue ball. At each stage, a ball is randomly chosen and then replaced along with another of the same color. Let X denote the selection number of the first chosen ball that is blue. For instance, if the first selection is red and the second blue, then X is equal to 2. (a) 17 points) Find POX a) for a 1. (b) 17 points Show that, with probability 1, a blue ball is eventually chosen, that is, show that P(X oo) 1. (Hint: Note that C (c) 16 points Find ETX]

Explanation / Answer

Initially the urn contain red ball = 1 and blue ball = 1

X = the selection number of the first chosen ball that is blue

X = 1 means first chosen ball is blue and the probablity = 1/2

X = 2 means first chosen ball is red and second chossen ball is blue and the probablity = (1/2)(1/3)

[ initially red = 1 and blue = 1 , P(R) = 1/2 and we replace the red ball along with another red ball and now red = 2 and blue = 1 so P(B) = 1/3 so P(RB) = (1/2)(1/3) ]

X = 3 means  first two chosen ball is red and third chossen ball is blue and the probablity = (1/2)(2/3)(1/4) = (1/3)(1/4)

[ initially red = 1 and blue = 1 , P(R) = 1/2 and we replace the red ball along with another red ball and now red = 2 and blue = 1 , so P(R) = 2/3 and again we replace the red ball along with another red ball and now red = 3 and blue = 1 so P(RRB) = (1/2)(1/3)(1/4) = (1/3)(1/4) ]

and X = 4, 5, ......so on

so the distribution of X

[ here 2.3 means 2 * 3 , 3.4 = 3 * 4]

(a) P(X >= a) = P(X= a) + P(X = a+1) + P(X = a+2) + P(X = a+3) + ..........................

=1/a(a+1) + 1/(a+1)(a+2) + 1/(a+2)(a+3) + 1/(a+3)(a+4) + .........................................

= 1/a

(b)P(X < infinity) = P(X=1) + P(X=2) + P(X=3) + P(X=4) + ................

= 1/2 + 1/2.3 + 1/3.4 + 1/4.5 + ............

= 1

(c) E[X] = (1 * 1/2) + (2 * 1/2.3) + (3 * 1/3.4) + (4 * 1/4.5) + ..........

= 1/2 + 1/3 + 1/4 + 1/5 + ..............

=

X 1 2 3 4 5 ............... fi 1/2 1/2.3 1/3.4 1/4.5 1/5.6 ...............