For the network shown Gi4) A(6) F(3) a-1. Determine the critical path O A-C-F-G

Question

For the network shown Gi4) A(6) F(3) a-1. Determine the critical path O A-C-F-G O A-C-E-G O A-B-E-G a-2. Determine the early completion time in weeks for the project. Early completion time For the data shown, reduce the project completion time by three weeks. Assume a linear cost per week shortened. 25 weeks NORMAL NORMAL CRASH CRASH ACTIVITY TIME COST TIME COST $ 7,400 5$13,500 18,300 7,000 6,000 6,700 7,500 8,400 12 12,200 7 5,800 4,600 3,200 2 7,000 2 8,000 3 4 b-1. Which activities in order of reduction would be shortened? ? G-D-D O G-E-A O D-B-C

Explanation / Answer

a-1

Paths and Its Duration

A-B-D-G = 6+12+3+4 = 25

A-C-E-G = 6+8+3+4 = 21

A-C-F-G = 6+8+3+4 = 21

Critical path of network is longest path in network

So Critical path is A-B-D-G with duration of 25 weeks

a-2 )

Early completion time of project = critical path duration = 25 days

b )

As critical path is A-B-D-G

So to shorten the project , activities in critical path should be shortened

for B , 5 weeks can be shortened with extra cost of 6100 so 1 week reduction will cause =1200 per week

For A , 1 week can be shortened with extra cost of 6100, so reduction cost per week of A = 6100

For D , 2 week reduction costs 1400, so reduction cost per week of D = 700

For G , 1 week reduction costs 400, so reduction cost per week of G = 400

Shortening order should be based on reduction cost per week of activities

We can see G can be reduced by max 1 week by 400

Next lowest cost reduction rate is for D and reduction is possible for 2 week

So order will be G-D-D

and additional cost = 400+2*700 = 1800

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects

---