The number of frog observers in the Frogwatch USA program (a wildlife conservati
ID: 3261082 • Letter: T
Question
The number of frog observers in the Frogwatch USA program (a wildlife conservation program dedicated to helping conserve frogs and toads) for the top 10 states with the most observers is below. Find the mean rounded to one decimal place (the tenths place) ex 53 7. 484, 483, 422, 396. 378, 352, 338, 331, 318, 302 _________ The number of frog observers in the Frogwatch USA program (a wildlife conservation program dedicated to helping conserve frogs and toads) for the top 10 states with the most observers is below. Find the median. 484, 483, 422, 396, 378, 352. 338, 331, 318, 302 ________ The number of frog observers in the Frogwatch USA program (a wildlife conservation program dedicated to helping conserve frogs and toads) for the top 10 states with the most observers is below. Find the mode 494, 483, 422, 396, 378, 352, 338, 331, 318, 302 If there is no mode, type "no mode" without the quotes, if there is mode write the mode(s) separated by commas. ________ Forbes Magazine prints an annual Top-Earning Nonliving Celebrities lists (based on royalties and estate earnings). Find the mean. Round to one decimal place lf needed example: 57.6. 50, 42, 35, 24, 20, 19. 10, 10, 8. 8, 7, 7, 7 ________ Forbes Magazine prints an annual Top-Earning Nonliving Celebrities lists (based on royalties and estate earnings). Find the median. 50, 42, 35, 24, 20, 19, 10.10. 8, 8, 7, 7, 7 _______ Forbes Magazine prints an annual Top-Earning Nonliving Celebrities lists (based on royalties and estate earnings). Find the mode. 50, 42, 35, 24, 20. 19. 10, 10, 8, 8, 7, 7, 7 7 no mode 12Explanation / Answer
question 1)380.4
QUESTION 2) median 365
question 3) NO MODE
question 4) 19 mean
question 5) median 10
question 6) mode 7
question 7) mean = 1500/30 = 50
question 8) The modal class (mode class) is the class with the highest frequency. In this case, the highest frequency is 12, which is the frequency for class 35-65