An oil exploration company has determined at a site that the oil discovery proba
ID: 3262274 • Letter: A
Question
An oil exploration company has determined at a site that the oil discovery probability is 0.65 per well. Assume that the oil exploration attempts, that is the wells, are independent,
What is the probability that unusual soil conditions will be found at third home site attempted for the first time?
What is the probability that unusual soil conditions will be found at three home sites our of 30 home sites planned for the subdivision?
What is the probability that no unusual soil conditions will be found at home sites for the 30 home sites planned for the subdivision?
Explanation / Answer
Answer to the questions with formulae :
Found ,p = .65 per well
Not found = 1-p = .35 per well
Applying Binomial theorm to solve the problem:
1. probability that unusual soil conditions will be found at third home site attempted for the first time =
P( not found for 1st 2 times)*P(found in the 3rd attempt)
= ((1-.35)^2)*(.65) = .2746
2.the probability that unusual soil conditions will be found at three home sites our of 30 home sites planned for
the subdivision
= 30C3(.65^3)(1-.35)^27 = 0.0099
3.
the probability that unusual soil conditions will be found at three home sites our of 30 home sites planned for the
subdivision
= 30C0(.65^0)(1-.35)^30 = .00000244