In the testing, whether the means of two normal populations are equal, summary s
ID: 3263516 • Letter: I
Question
In the testing, whether the means of two normal populations are equal, summary statistics computed for two independent samples are as follows
N2 = 35
S2 = 1.20
assume that the population variances are equal. What is the value of the Test statistic you would use to test the claim that the two means are not equal?
a) 1.607 b) 1.611 c) 1.553 d) 1.319
For test statistic formula, should i use the one with pooled variance (S2p) or not?
Brand X Brand Y N1 = 20N2 = 35
X1bar = 7.30 X2 bar = 6.80 S1 = 1.05S2 = 1.20
Explanation / Answer
Data:
n1 = 20
n2 = 35
x1-bar = 7.3
x2-bar = 6.8
s1 = 1.05
s2 = 1.2
Hypotheses:
Ho: 1 = 2
Ha: 1 2
Decision Rule:
= 0.05
Degrees of freedom = 20 + 35 - 2 = 53
Lower Critical t- score = -2.005745949
Upper Critical t- score = 2.005745949
Reject Ho if |t| > 2.005745949
Test Statistic:
Pooled SD, s = [{(n1 - 1) s1^2 + (n2 - 1) s2^2} / (n1 + n2 - 2)] = (((20 - 1) * 1.05^2 + (35 - 1) * 1.2^2)/(20 + 35 -2)) = 1.148
SE = s * {(1 /n1) + (1 /n2)} = 1.14848135986714 * ((1/20) + (1/35)) = 0.321926165
t = (x1-bar -x2-bar)/SE = 1.553151172
Option C.