Stats homework help...how to find the p value?? PLEASE ANSWER ALL. For every foo
ID: 3268224 • Letter: S
Question
Stats homework help...how to find the p value?? PLEASE ANSWER ALL.
For every football game there is a team that is expected to win by a certain number of points. In betting parlance, this is called the spread. If point spreads are accurate, we would expect about half of all games played to result in the favored team winning (beating the spread) and about half of all games to result in the team favored to not beat the spread. The accompanying data represent the results of 45 randomly selected games where a 0 indicates the favored team did not beat the spread and a 1 indicates the favored team beat the spread. Do the data suggest that sport books establish accurate spreads? Click the icon to view the spread results. Identify the correct null and alternative hypotheses. Ho : pl 10.5 Find the P-value P-value-(Round to three decimal places as needed.) Do the data suggest that sport books establish accurate spreads? O A. Do not reject Ho Although no level of significance is given, the data suggest the spreads are accurate. O B. Reject Ho.Although no level of significance is given, the data do not suggest the spreads are accurate. O C. Reject Ho.Although no level of significance is given, the data suggest the spreads are accurate O D. Do not reject Ho Although no level of significance is given, the data do not suggest the spreads are accurate.Explanation / Answer
Solution
Let X = Number of parents who feel that it was a serious problem that high school students are not taught enough math and science. Then,
X ~ B(n, p), where n = sample size (250) and p = probability of a parent feeling the above = proportion of parents feeling as above.
We want to test if p = 0.32 or not.
Claim: Parents feel differently now.
Back-up Theory
Test statistic: Z = (pcap – 0.32)/sqrt{0.32(1 – 0.32)/250}
= {(85/250) – 0.32}/sqrt(0.0008704)
= 0.02/0.0295
= 0.6779
Part (a)
H0: p = 0.32 Vs H1: p 0.32 [H1 represents the claim.]
Part (b)
Under H0, Z ~ N(0, 1) and hence p-value = P(| Z | > 0.6779) = 0.502 [using Excel Function]
Thus, p-value = 0.502
Part (c)
Since p-value > 0.1(given level of significance), H0 is accepted. => there is not enough evidence to suggest that parents feel differently now. option C ANSWER