Brazilian scientists have identified an new strain of the H1N1 virus. The geneti
ID: 3271819 • Letter: B
Question
Brazilian scientists have identified an new strain of the H1N1 virus. The genetic sequence of the new strain consists of alterations in the hemagglutin protein, making it significantly different from the usual H1N1 strain. Public health officials wish to study the population of residents in Rio de Janeiro. Suppose that in this population the probability of catching the usual strain is .10, the probability of catching the new strain is .05, and the probability of catching both strains is .01. a. In this setting, are the events "catching the usual strain" and "catching the new strain" mutually exclusive? Why? b. What is the probability of not catching the new strain? c. What is the probability of catching exactly one type of strain? d. What is the probability of catching the usual type but not the old type? e. What is the probability of catching at least one of the two strains? f. What is the probability of not catching neither one of the two strains?Explanation / Answer
(According to Chegg policy only four subquestions will be answered. Please post the remaining in another question)
a. The two events are indeed mutually exclusive as the outcome of one does not depend on another.
b. Probability of catching the new stain = 0.05
=> Probability of not catching the new stain = 1 - 0.05 = 0.95
c. The probability of catching the usual stain = 0.1
The probability of catching new stain = 0.05
The probability of catching both stains = 0.01
=> The probability of catching exactly one type of stain = 0.1 + 0.05 - 2*0.01 = 0.13
d. (The question has a problem. Some "old type" is mentioned which is not a part of the question. Neverthess the answer is as below)
The probability of catching the usual stain = 0.1
The probability of catching both stains = 0.01
=> Probability of catching usual stain - 0.01 = 0.09