Construct one table that includes relative frequencies based on the frequency di
ID: 3272496 • Letter: C
Question
Construct one table that includes relative frequencies based on the frequency distributions shown below, then compare the amounts of tar in nonfiltered and filtered cigarettes. Do the cigarette filters appear to be effective? (Hint: The filters reduce the amount of tar ingested by the smoker.) Click the icon to view the frequency distributions Relative Relative Frequency Frequency ered) Tar (mg) Nonfitered) 6-10 11-15 16-20 21-25 26-30 31-35 36-40 (Simplifty your answers) Do cigarette filters appear to be effective? A. B. ° C. 0 D. Yes, because the relative frequency of the higher tar classes is greater for nonfiltered cigarettes. No, because the relative frequency of the higher tar classes is greater for filtered cigarettes. No, because the relative frequencies for each are not substantially diferent. This cannot be determinedExplanation / Answer
The total frequency for nonfiltered cigarettes is computed as: 1 + 0 + 16 + 7 +1 = 25
The total frequency for filtered cigarettes is computed as: 2 + 1 + 5 + 17 = 25
The relative frequencies are computed by dividing the frequencies by 25 ( which is the total frequency ) Therefore now the relative frequencies are computed as;
Clearly the filter is effective because the relative frequencies are clearly higher for higher tar classes in nonfiltered cigarettes.
Tar (mg) Frequency ( Nonfiltered ) Frequency ( Filtered ) Relative Frequency (Nonfiltered) Relative Frequency (Filtered ) 6-10 0 2 0 2/25 = 0.08 11-15 0 1 0 1/25 = 0.04 16-20 1 5 1/25 = 0.04 5/25 = 0.2 21-25 0 17 0 17/25 = 0.68 26-30 16 0 16/25 = 0.64 0 31-35 7 0 7/25 = 0.28 0 36-40 1 0 1/25 = 0.04 0