Coulomb\'s Law describes the force between two (and only two) charged objects. S
ID: 3278810 • Letter: C
Question
Coulomb's Law describes the force between two (and only two) charged objects. Suppose Object 1 has a charge of +3.34 mu C and Object 2 has a charge of +14.6 mu C Object 2 is located a distance of 0.05270 m to the right of Object 1 (Yes - please break down and draw a quick sketch). What is the magnitude and direction of the electrical force on Object 2 due to Object 1? to the left to the right What is the magnitude and direction of the electrical force on Object 1 due to Object 2? to the left to the right You now move Object 2 such that it is located a distance of 0.1054 m to the right of Object 1 (twice the distance as before). What is the magnitude and direction of the electrical force on Object 2 due to Object 1? to the left to the right The new force on Object 1 due to Object 2 (at a separation of 0.1054 m) is _____times the original force on Object 1 due to Object 2 (at a separation of 0.05270 m)? (Provide a numerical answer to fill in the blank)Explanation / Answer
Here , for object 2
as the force is repulsive
the force on object 2 is towards right
magnitude of force on object 2 = 9 *10^9 * (14.6 *10^-6 * 3.34 *10^-6)/.05270^2
magnitude of force on object 2 = 158.02 N
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on the object 1
as the force is equal and oposite
the magnitude of force is 158.02 N and the direction is to the left
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as the distance is doubled
the electric force will be 1/4 th
hence , on object 2 is towards right
magnitude of force = 158.02/4 = 39.5 N
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for the object 1
as the force is equal and oposite
the magnitude of force is 39.5 N and the direction is to the left