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A recently negotiated union contract allows workers in a shipping department 19

ID: 328018 • Letter: A

Question

A recently negotiated union contract allows workers in a shipping department 19 minutes for rest, 10 minutes for personal time, and 11 minutes for delays for each four hours worked. A time study analyst observed a job that is performed continuously and found an average time of 7.0 minutes per cycle for a worker she rated at 92 percent of the observed time. What standard time is applicable for that operation? (Keep two decimal places in your answer) A recently negotiated union contract allows workers in a shipping department 19 minutes for rest, 10 minutes for personal time, and 11 minutes for delays for each four hours worked. A time study analyst observed a job that is performed continuously and found an average time of 7.0 minutes per cycle for a worker she rated at 92 percent of the observed time. What standard time is applicable for that operation? (Keep two decimal places in your answer) A recently negotiated union contract allows workers in a shipping department 19 minutes for rest, 10 minutes for personal time, and 11 minutes for delays for each four hours worked. A time study analyst observed a job that is performed continuously and found an average time of 7.0 minutes per cycle for a worker she rated at 92 percent of the observed time. What standard time is applicable for that operation? (Keep two decimal places in your answer) A recently negotiated union contract allows workers in a shipping department 19 minutes for rest, 10 minutes for personal time, and 11 minutes for delays for each four hours worked. A time study analyst observed a job that is performed continuously and found an average time of 7.0 minutes per cycle for a worker she rated at 92 percent of the observed time. What standard time is applicable for that operation? (Keep two decimal places in your answer)

Explanation / Answer

To be calculated:

Standard time

Given values:

Rest time = 19 minutes

Personal time = 10 minutes

Delay time = 11 minutes

Total time = 4 hours = 4 x 60 = 240 minutes

Average time = 7 minutes per cycle

Worker rating = 92 percent = 0.92

Solution:

Allowance factor can be calculated as;

Allowance factor (AF) = Allowed time / Total time

Allowance factor (AF) = (19 + 10 + 11) / 240

Allowance factor (AF) = 40 / 240

Allowance factor (AF) = 0.167

Normal time = Average time x Worker rating

Normal time = 7 x 0.92

Normal time = 6.44 minutes

Standard time is calculated as;

Standard time = Normal time / (1 - Allowance factor)

Standard time = 6.44 / (1 - 0.167)

Standard time = 7.73 minutes